TSTP Solution File: PUZ137^1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : PUZ137^1 : TPTP v8.1.2. Released v5.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n009.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 13:14:51 EDT 2023

% Result   : Theorem 3.34s 3.56s
% Output   : Proof 3.34s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem    : PUZ137^1 : TPTP v8.1.2. Released v5.3.0.
% 0.10/0.13  % Command    : duper %s
% 0.12/0.34  % Computer : n009.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit   : 300
% 0.12/0.34  % WCLimit    : 300
% 0.12/0.34  % DateTime   : Sat Aug 26 22:03:50 EDT 2023
% 0.12/0.34  % CPUTime    : 
% 3.34/3.56  SZS status Theorem for theBenchmark.p
% 3.34/3.56  SZS output start Proof for theBenchmark.p
% 3.34/3.56  Clause #0 (by assumption #[]): Eq (says peter (∀ (X : Prop), says peter X → Not X)) True
% 3.34/3.56  Clause #1 (by assumption #[]): Eq (Not (∀ (X : Prop), says peter X)) True
% 3.34/3.56  Clause #2 (by clausification #[1]): Eq (∀ (X : Prop), says peter X) False
% 3.34/3.56  Clause #3 (by clausification #[2]): ∀ (a : Prop), Eq (Not (says peter (skS.0 0 a))) True
% 3.34/3.56  Clause #4 (by clausification #[3]): ∀ (a : Prop), Eq (says peter (skS.0 0 a)) False
% 3.34/3.56  Clause #5 (by identity loobHoist #[4]): ∀ (a : Prop), Or (Eq (says peter True) False) (Eq (skS.0 0 a) False)
% 3.34/3.56  Clause #6 (by identity boolHoist #[4]): ∀ (a : Prop), Or (Eq (says peter False) False) (Eq (skS.0 0 a) True)
% 3.34/3.56  Clause #7 (by identity loobHoist #[5]): ∀ (a : Prop), Or (Eq (says peter True) False) (Or (Eq (skS.0 0 True) False) (Eq a False))
% 3.34/3.56  Clause #9 (by bool simp #[0]): Eq (says peter (And (says peter True → Not True) (says peter False → Not False))) True
% 3.34/3.56  Clause #10 (by bool simp #[9]): Eq (says peter (And (says peter True → Not True) (says peter False → True))) True
% 3.34/3.56  Clause #11 (by bool simp #[10]): Eq (says peter (And (says peter True → Not True) True)) True
% 3.34/3.56  Clause #12 (by bool simp #[11]): Eq (says peter (says peter True → Not True)) True
% 3.34/3.56  Clause #13 (by bool simp #[12]): Eq (says peter (says peter True → False)) True
% 3.34/3.56  Clause #14 (by bool simp #[13]): Eq (says peter (Not (says peter True))) True
% 3.34/3.56  Clause #15 (by identity loobHoist #[14]): Or (Eq (says peter True) True) (Eq (Not (says peter True)) False)
% 3.34/3.56  Clause #16 (by identity boolHoist #[14]): Or (Eq (says peter False) True) (Eq (Not (says peter True)) True)
% 3.34/3.56  Clause #17 (by clausification #[15]): Or (Eq (says peter True) True) (Eq (says peter True) True)
% 3.34/3.56  Clause #18 (by eliminate duplicate literals #[17]): Eq (says peter True) True
% 3.34/3.56  Clause #19 (by backward demodulation #[18, 7]): ∀ (a : Prop), Or (Eq True False) (Or (Eq (skS.0 0 True) False) (Eq a False))
% 3.34/3.56  Clause #20 (by clausification #[16]): Or (Eq (says peter False) True) (Eq (says peter True) False)
% 3.34/3.56  Clause #21 (by forward demodulation #[20, 18]): Or (Eq (says peter False) True) (Eq True False)
% 3.34/3.56  Clause #22 (by clausification #[21]): Eq (says peter False) True
% 3.34/3.56  Clause #23 (by clausification #[19]): ∀ (a : Prop), Or (Eq (skS.0 0 True) False) (Eq a False)
% 3.34/3.56  Clause #24 (by forward demodulation #[6, 22]): ∀ (a : Prop), Or (Eq True False) (Eq (skS.0 0 a) True)
% 3.34/3.56  Clause #25 (by clausification #[24]): ∀ (a : Prop), Eq (skS.0 0 a) True
% 3.34/3.56  Clause #26 (by identity loobHoist #[25]): ∀ (a : Prop), Or (Eq (skS.0 0 True) True) (Eq a False)
% 3.34/3.56  Clause #29 (by falseElim #[26]): Eq (skS.0 0 True) True
% 3.34/3.56  Clause #32 (by superposition #[29, 23]): ∀ (a : Prop), Or (Eq True False) (Eq a False)
% 3.34/3.56  Clause #33 (by clausification #[32]): ∀ (a : Prop), Eq a False
% 3.34/3.56  Clause #35 (by falseElim #[33]): False
% 3.34/3.56  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------